1.

A metal oxide has the formula X_(2)O_(3). It can be reduced by hydrogen to give free metal and water. 0.1596g of metal oxide requires 6 mg of hydrogen for complete reduction . The atomic mass of metal in amu is:

Answer»

15.58
155.8
5.58
55.8

Solution :`X_(2)O_(3)+3H_(2)rarr2X+3H_(2)O`
1MOL 3 MOL
(2a+48)g 6g
0.006 g `H_(2)` is required by 0.1596 g oxide
`THEREFORE 6g H_(2)` will be required by 159.6 g oxide
`therefore 2a+48=159.6`
a=55.8


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