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A metal rod of length 2.5m and area of cross-section `2.5xx10^(-4)m^(2)` is elongated by `2.5xx10^(-3)`m by a force of 600N. Then energy stored in the rod is,A. 75 JB. 0.75 JC. 25 JD. 50 J |
Answer» Correct Answer - B `W=(1)/(2)Fl` `=(1)/(2) xx 600 xx 2.5xx10^(-3)=0.75J`. |
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