A Metal Sheet 27 Cm Long 8cm Broad And 1 Cm Thick Is Melted Into A Cu

1.	A Metal Sheet 27 Cm Long 8cm Broad And 1 Cm Thick Is Melted Into A Cube. The Difference Between The Surface Areas Of Two Solids Is?
Answer» Volume of sheet = (27 × 8 × 1)cm3 = 216 cm3 Volume of cube FORMED = 216 cm3 Therefore, EDGE of the cube = (6 × 6 × 6)1/3 = 6 cm SURFACE area of original cuboid = 2 (27 × 8 + 8 × 1 + 27 × 1) cm2 = 502 cm2 Surface area of the cube formed = [6 × (6) 2] cm2 = 216 cm2 Therefore, Difference in AREAS = (502 - 216)cm2= 286 cm2. Volume of sheet = (27 × 8 × 1)cm3 = 216 cm3 Volume of cube formed = 216 cm3 Therefore, Edge of the cube = (6 × 6 × 6)1/3 = 6 cm Surface area of original cuboid = 2 (27 × 8 + 8 × 1 + 27 × 1) cm2 = 502 cm2 Surface area of the cube formed = [6 × (6) 2] cm2 = 216 cm2 Therefore, Difference in areas = (502 - 216)cm2= 286 cm2.

A Metal Sheet 27 Cm Long 8cm Broad And 1 Cm Thick Is Melted Into A Cube. The Difference Between The Surface Areas Of Two Solids Is?

Answer»

Volume of sheet = (27 × 8 × 1)cm3 = 216 cm3

Volume of cube FORMED = 216 cm3

Therefore, EDGE of the cube = (6 × 6 × 6)1/3 = 6 cm

SURFACE area of original cuboid = 2 (27 × 8 + 8 × 1 + 27 × 1) cm2 = 502 cm2

Surface area of the cube formed = [6 × (6) 2] cm2 = 216 cm2

Therefore, Difference in AREAS = (502 - 216)cm2= 286 cm2.

Volume of sheet = (27 × 8 × 1)cm3 = 216 cm3

Volume of cube formed = 216 cm3

Therefore, Edge of the cube = (6 × 6 × 6)1/3 = 6 cm

Surface area of original cuboid = 2 (27 × 8 + 8 × 1 + 27 × 1) cm2 = 502 cm2

Surface area of the cube formed = [6 × (6) 2] cm2 = 216 cm2

Therefore, Difference in areas = (502 - 216)cm2= 286 cm2.