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A metal X crystallises in a face-centred cubic arrangement with the edge length 862 pm. What is the shortest separation of any two nuclei of the atom ?A. 406 pmB. 707 pmC. 862 pmD. 609.6 pm

Answer» Correct Answer - D
For fcc arrangement , distance of nearest neighbour (d) is `a/sqrt2=862/1.414`=609.6 pm


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