InterviewSolution
Saved Bookmarks
| 1. |
A metal X crystallises in a face-centred cubic arrangement with the edge length 862 pm. What is the shortest separation of any two nuclei of the atom ?A. 406 pmB. 707 pmC. 862 pmD. 609.6 pm |
|
Answer» Correct Answer - D For fcc arrangement , distance of nearest neighbour (d) is `a/sqrt2=862/1.414`=609.6 pm |
|