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A metallic bob weighs 50 g in air. If it is immersed in a liquid at a temperature of 25^(@)C, it weighs 45g. When the temperature of the liquid is raised to 100^(@)C, it weighs 45.1 g. Calculate the coefficient of cubical expansion of liquid assuming the linear expansion of the metal to be 1.2 xx 10^(-5) //K. |
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Answer» Solution :`(v _(1))/(v _(0)) (d _(1))/( d _(0)) = (4.9)/( 5) = ( V _(0) (1 + GAMMA _(1) x ) d _(0))/(d _(0) V _(0) (1 + gamma _(2) x )) = (1 + 75 gamma _(1))/( 1 + 75 gamma _(2)) = (49)/(50) therefore L = 75 x 49 gamma _(2) - 75 xx 50 gamma _(1)` `implies 75 (49 gamma _(2) - ( 50 xx 3.6)/(10 ^(5)))_ = 1 implies gamma = 0.000308//K.` It is a matter of common experience that bodies. |
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