1.

A metallic chloride A when treated with sodium hydroxide and H_(2)O_(2) gives a yellow solution due to the formafion of compound B. The colour of this solution changes to orange yellow when dilute H_(2)SO_(4) is added to it due to formation of (C). Compound, (D) when heated with (C) in presence of conc. H_(2)SO_(4) a red volatile liquid E is formed. E dissolves in NaOH giving yellow solution B, which changes to yellow ppt. Fon treatment with lead acetate. (C) on reaction with NH_(4)Cl gives G which on heating gives colourless gas (H and a green residue (1). Identify (A) to (I).

Answer»

SOLUTION :`UNDERSET((A))(2CrCI_(2))+10NaOH+3H_(2)O_(2)tounderset((B))(2Na_(2)CrO_(4))+6NaCl+8H_(2)O`
`underset((B))(2Na_(2)CrO_(4))+H_(2)SO_(4)tounderset((C))(Na_(2)Cr_(2)+O_(7))+Na_(2)SO_(4)+H_(2)O`
`underset((D))(4NaCI)+Na_(2)Cr_(2)O_(7)+6H_(2)SO_(4)tounderset((E))(2CrO_(2)Cl_(2))+6NaHSO_(4)+3H_(2)O`


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