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A metallic crystal crystallizes into lattice containing a sequence of layers AB,AB,AB. . .. . . . .. ... The percentage of free space in this lattice isA. 0.74B. 0.26C. 0.32D. 0.48 |
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Answer» Correct Answer - B It is FCC packing Volume occupied `=(4(4)/(3)m^(3))/(a^(3)) [4r=sqrt(2)arArra=2sqrt(2)r]` `=(4xx(4)/(3)m^(3))/((2sqrt(2)r)^(3))=(16)/(3)xx(1)/(16sqrt(2))pi=(pi)/(3sqrt(2))=(3.142)/(3xx1.414)=0.74` Volume occupied is 74%, free space =26% |
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