A metallic element exists as a cubic lattice. Each edge of the unit cell is 2.88Å. The density of the metal is 7.20 gcm^(-3). How many unit cells there will be in 100g of the metal ?

A metallic element exists as a cubic lattice. Each edge of the unit ce

1.	A metallic element exists as a cubic lattice. Each edge of the unit cell is 2.88Å. The density of the metal is 7.20 gcm^(-3). How many unit cells there will be in 100g of the metal ?
Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/volume-728707" style="font-weight:bold;" target="_blank" title="Click to know more about VOLUME">VOLUME</a> of unit cell = `(2.88 Å )^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) = 23.9 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10^(-24) cm^(3)` <br/> Volume of 100 g of the metal = `(m)/(<a href="https://interviewquestions.tuteehub.com/tag/rho-623364" style="font-weight:bold;" target="_blank" title="Click to know more about RHO">RHO</a>)` <br/> `= 100= 13.9 cm^(3)` <br/> Number of unit cells in this volume = `(139 cm^(3))/(23.9 xx 10^(-24) cm^(3)) = 5.82 xx 10^(23)`</body></html>