A metallic rod of mass 20 kg and of uniform thickness rests against a wall while the lower end of the rod is in contact with floor. The rod makes an angle of 60o with floor. If the weight of rod produces a torque 150 Nm about its lower end, the length of the rod is (g = 10ms−2)

A metallic rod of mass 20 kg and of uniform thickness rests against a

1.	A metallic rod of mass 20 kg and of uniform thickness rests against a wall while the lower end of the rod is in contact with floor. The rod makes an angle of 60o with floor. If the weight of rod produces a torque 150 Nm about its lower end, the length of the rod is (g = 10ms−2)
Answer» A metallic rod of mass 20 kg and of uniform thickness rests against a wall while the lower end of the rod is in contact with floor. The rod makes an angle of $60^{o}$ with floor. If the weight of rod produces a torque 150 Nm about its lower end, the length of the rod is (g = 10 $m s^{- 2}$ )

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A metallic rod of mass 20 kg and of uniform thickness rests against a wall while the lower end of the rod is in contact with floor. The rod makes an angle of 60o with floor. If the weight of rod produces a torque 150 Nm about its lower end, the length of the rod is (g = 10ms−2)

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