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A meteal crystallises into two cubic phases, face-centred (FCC) and body -centred cubic (BCC)whose unit celllengths are 3.5 and 3.0 Årespectively.Calculate the ratio of the densitiesof FCC and BCC. |
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Answer» <P> Solution :`(p_("FCC"))/(p_("BCC"))= (Z_("FCC"))/((a^(3)) _("FCC")) XX ((a^(3))_("BCC"))/(Z_("BCC")) = (4 xx (3.0)^(3))/(2 xx (3.5)^(3)) = 1.26 ` |
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