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A meter has a full scale of 90° at a current of 1 A. This meter has a perfect square law response. What is the current when the deflection angle is 45°?(a) 0.5 A(b) 0.25 A(c) 0.707 A(d) 0.67 AThe question was posed to me in unit test.This interesting question is from Advanced Problems on Indicating Instruments topic in division Extension of Instrument Ranges of Electrical Measurements

Answer»

Right option is (c) 0.707 A

Easy explanation: We know,TD = Cθ

Also, TD = KI^2

∴ I^2 = \(\FRAC{C}{K}\) θ = C’θ

Or, \(\frac{I^2}{I} = \frac{C’ π}{C’ \frac{\PI}{2}} = \frac{1}{2}\)

So, I = 0.707 A.


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