A mild steel wire of length1.0 m andcross-sectional area 0.50xx10^(-2) cm^(-2) is stretched,well within its elastic limit, horizontally between two pillars.A mass of 100 g is suspendedfrom the mid-point of the wire. Calculate the depression at the mid-point.

A mild steel wire of length1.0 m andcross-sectional area 0.50xx10^(-2)

1.	A mild steel wire of length1.0 m andcross-sectional area 0.50xx10^(-2) cm^(-2) is stretched,well within its elastic limit, horizontally between two pillars.A mass of 100 g is suspendedfrom the mid-point of the wire. Calculate the depression at the mid-point.
Answer» Solution :`x=l[(Mg)/(YA)]^(1//3)` Here, `m 2l=1m, l=0.5m`, `A=0.50xx10^(-6) m^(2) , , M=0.1 kg`, `Y=2xx10^(11) N//m^(2) and g=10m//s^(2)` `therefore` DEPRESSION `x=1.074xx10^(-2)m`