| 1. |
A military tent of height 8.25 m is in the form of a right circular cylinder of base diameter 30 m and height 5.5 m surmounted by a right circular cone of same base radius. Find the length of canvas used in making the tent, if the breadth of the canvas is 1.5 m. |
|
Answer» A military tent is made as a combination of right circular cylinder and right circular cone on top. Given : Total Height of tent = h = 8.25 m Base diameter of tent = 30 m, then Base radius of tent = r = 30/2 m = 15 m Height of right circular cylinder = 5.5 m Base radius of cone = 15 m Let slant height of cone = l m Now, Curved surface area of right circular cylindrical part of tent = 2πrh and Height of conical part = total height of tent – height of cylindrical part Height of cone = 8.25 – 5.5 = 2.75 m l2 = h2 + r2 = 2.752 + 152 = 232.5625 or l = 15.25 m Curved surface area of conical part of the tent = πrl Total surface area of the tent = Curved surface area of cylindrical part + curved surface area of conical part Total surface area of tent = 2πrh + πrl = πr(2h + l) = 22/7 × 15 × (2 × 5 = 1237.5 Total surface area of tent is 1237.5 m2 Breadth of canvas used = 1.5 m Length of canvas used x breadth of canvas used = Total surface area of tent Length of canvas used = 1237.5\1.5 = 825 Length of canvas used is 825 m. Answer!! |
|