1.

A milkman has two types of milk. In the first container the percentage of milk is 80% and in the second container the percentage of milk is 60%. If he mixes 28 liters of milk of the first container to the 32 liters of milk of the second container, then percentage of milk in the mixture is :

Answer»

69.99
69.33
72.5
75.2

Solution :
So,`(80-60)XX7/(7+8) = 20xx7/(15) = 69.33`


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