1.

A mix. of CaH2 & C3Hg occupied a certain volume at 80 mm. The mix was completely burnt into CO2& H2O (). When the pressure of CO2 was found to be 230 mm at same T & V. Find mole fraction ofC3Hs in mix.(0.875)

Answer»

C_2 H_2+(2+2/4) O_2→2CO_2+H_2 OC_3 H_8+(3+8/4) O_2→3CO_2+4H_2 Ox+y=802x+3y=2302(80-y)+3y=230y=70.The fraction of C3H8 in the mixture is70/80 100%=87.5%



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