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A mixture contaning `1 mol` each of `CO` and `O_(2)` is exploded to produce `CO_(2)`. Which of the following is/are correct ?A. If `%` yield of reaction is `80%`, only `0.8` mole `CO_(2)` is formed.B. Oxygen is limiting reagent.C. Volume of final gaseous mixture is `33.6L` at `STP`, if `%` yield is `100%`D. `%` excess of excess reagent is `40%`, if `%` yield is `100%` |
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Answer» Correct Answer - A::C `{:(2CO,+,O_(2)rarr,2CO_(2),),(,,CO is L.R. ,, O_(2) "is excess reagent"),(t=t,,1mol, 1mol),(t=t,o mol,1/2mol,mol("If % yield is 100%")):}` Total gaseous moles `= 1 + (1)/(2) = 1.5 mol` `:.` Volume of final mixture `1.5 xx 22.4 = 33.6L` `%` excess of `O_(2) = (1//2"mol")/(1//2"mol") xx 100 = 100%` If `%` yield `= 80` `= ("Actual moles of" CO_(2) "formed")/("moles of" CO_(2) ("accoding to stoichiometry"))xx 100` `80 = ("Moles of" CO_(2)"formed")/(1) xx 100` `:.` Actual moles formed `= 0.8 mol` |
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