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A mixture of 0.02 mole of `KBrO_(3)` and `0.001` mole of `KBr` was treated with excess of KI and acidified. The volume of 0.01M `Na_(2)S_(2)O_(3)` solution required to consume the liberated iodine will be :A. 1000mLB. 1200mLC. 1500mLD. 800mL |
Answer» Correct Answer - b |
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