1.

A mixture of 30 liters of milk and water contains milk and water in the ratio of 7 : 3. How much water must be added to it. so that the ratio of milk to water be reserved i.e. 3 : 7?1). 40 ltr2). 45 ltr3). 42 ltr4). 49 ltr

Answer»

Milk contents in the mixture $(= \frac{7}{{10}} \TIMES 30 = 21\;{\rm{liters}})$

Water = 9 liters

In the new mixture, the ratio of milk to water is 3 : 7

In 21 liters of milk water is $(\frac{7}{3} \times 21 = 49\;{\rm{liters}})$

Water to be ADDED = 49 - 9 = 40 liters


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