a mixture of CS2 and H2S when oxidized earrings a mixture of Co2 and SO2 and H2O which exerts a pressure of 740 8.8 mm of HG when connected in 60 litres vessel at 3 27 degree Celsius to oxidized Asher 2 and the mixture 700 ml of 2 and iodide where required what was the mole fraction of CS in the mixture

a mixture of CS2 and H2S when oxidized earrings a mixture of Co2 and S

1.	a mixture of CS2 and H2S when oxidized earrings a mixture of Co2 and SO2 and H2O which exerts a pressure of 740 8.8 mm of HG when connected in 60 litres vessel at 3 27 degree Celsius to oxidized Asher 2 and the mixture 700 ml of 2 and iodide where required what was the mole fraction of CS in the mixture
Answer» hii mate here is your answer Explanation:According to question ,CS 2 +3O 2 →CO 2 +2SO 2 __________(1)2H 2 S+3O 2 →2H 2 O+2SO 2 ____________(2)Total moles of gases SO 2 ,CO 2 and H 2 O exerted.pressure,n= RTPV = 0.0821×6007.2×82.1 n= 49.26591.12 = 12 moles.when I 2 react with SO 2 I 2 +SO 2 +2H 2 O→2HI+H 2 SO 4 moles of I 2 REQ. = 5×2 = 10It means only 10 mole SO 2 releasedand 12-10=2 moles other gases (CO 2 ,H 2 O)According to eq (1) and (2).2 mole SO 2 = 1 mole CS 2 10 mole SO 2 = 210 = 5 mole CS 2 Rest 2 mole gas also given by 2 mole CS 2 So,Total moles of CS 2 in mixture = 5 + 2 = 7Answer = 7