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A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290 mm at 300K. The vapour pressure of propyl alcohol is 200 mm. if the mole fraction of ethyl alcohol is `0.6`, its vapour pressure (in mm) at the same temperature will beA. 350B. 300C. 360D. 700 |
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Answer» Correct Answer - A Mole fraction of ethyl alcohol = 0.6 Mole fraction of methyl alcohol = 0.4 A rarr Ethyl alcohol & B rarr Methyl alcohol Then `P_(T) = P_(A)^(@) X_(A) + P_(B)^(@) X_(B)` `290 = (P_(A)^(@) xx 0.60)+(200 xx 0.40) ` ` P_(A)^(@)`= (290-80)/0.60=350 mm |
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