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A mixture of formic acid and oxalic acid is heated with conc. `H_(2)SO_(4)`. The gas producted is collected and treated with `KOH` solution, whereby the volume decrease by `1//6th`. The molar ratio of the two acids (formic acid/oxalic acid) isA. `4:1`B. `1:4`C. `2:1`D. `1:2` |
Answer» Correct Answer - A Let `x` mol of `HCOOH` and `y` mol of `COOH)_(2)`. `underset(x)(HCOOH) overset(H_(2)SO_(4))rarr H_(2) + underset(x)(CO)` `underset(x)((COOH)_(2)) overset(H_(2)SO_(4))rarr H_(2)O + underset(x)(CO) + underset(y)(CO_(2))` Total moles of `(CO + CO_(2)) = x + 2y` Total moles of `CO_(2) = y` According to the question: `(x + 2y) xx (1)/(6) = y` `:. (x)/(y) = 4:1` Alternatively: Mole fraction of `CO_(2) = (y)/(x + 2y) = (1)/(6)` `:. (x)/(y) = 4:1` |
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