Saved Bookmarks
| 1. |
A mixture of He and `O_(2)` has density `1.3 gm//`litre at NTP. Them mole fraction of He isA. `0.1`B. `0.9`C. `0.4`D. `0.6` |
|
Answer» Correct Answer - A `d = 1.3 gm//"litre" = (PM)/(RT)` `1.3 = (1 xx M)/(0.08 xx 273)` `M = 1.3 xx 22.4` `M = 29.12 gm//mol` `M_(avg) = M_(1)X_(1) xx M_(2) X_(2)` `29.12 = 4a + 32 - 32a` `29.12 = 32 - 28a` `28a = 32 - 29.12` `a = (2.88)/(28)` `a = 0.1` Hence, `X_(O_(2)) = 0.9` `X_(He) = 0.1` |
|