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A mixture of `O_(2)` and gas `"Y"` `( mol. wt. 80)` in the mole ratio `a:b` has a mean molecular weight 40. What would be mean molecular weight, if the gases are mixed in the ratio `b:a` under identical conditions ? ( gases are )A. 40B. 48C. 62D. 72 |
Answer» Correct Answer - 4 Let mole fraction of `O_(2)` is `x` `40=32xx x+80(1-x)" "`or `" " x=5//6` `a+b=x:(1-x)=(5)/(6):(1)/(6)` When ratio is changed `M_("mixture")=32xx(1)/(6)+80xx(1)/(6)=72` |
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