A mixture of three protiens, `(A)` (pepsin), `(B)` (haemo-globin), and `(C )` (lysozyme) was seperated by elctrophoresis method at `pH=7`. The `pH` at isoelectric point `(pI)` of the proteins are `pI` of `(A)`, `(B)`, and `(C )` which are `1.1,6.7`, and `11.0`, respectively. which of the statement are correct?A. Pepsin (A) will migrate to the cathode.B. Lysozyme (C ) will migrate to the anode.C. Haemoglobon will not migrate.D. At pH=7, (A) and (C ) would precipitate out while (B) would remain in the solution.

A mixture of three protiens, `(A)` (pepsin), `(B)` (haemo-globin), and

1.	A mixture of three protiens, `(A)` (pepsin), `(B)` (haemo-globin), and `(C )` (lysozyme) was seperated by elctrophoresis method at `pH=7`. The `pH` at isoelectric point `(pI)` of the proteins are `pI` of `(A)`, `(B)`, and `(C )` which are `1.1,6.7`, and `11.0`, respectively. which of the statement are correct?A. Pepsin (A) will migrate to the cathode.B. Lysozyme (C ) will migrate to the anode.C. Haemoglobon will not migrate.D. At pH=7, (A) and (C ) would precipitate out while (B) would remain in the solution.
Answer» Correct Answer - A::B::C Is in a very acidic range, has more anionic groups at `pH=7`, and will migrate to the positive electrode (cathode). `(B)(pI=6.7)` is present mostly with net zero charge and moves very littel or will not migrate. `(C )(pH=11.0)`, the very basic protein, exists mainly in the cationic form and migrates to the negative electrode (anode). At `pI`, amino acids have least solubities, so `(B)` `(pH=6.7)`, `[pH` very close to `pH` of the mixture `(pH=7)]`, is least soluble and would precipitate out, while `(A)` and `(C )` would remain in the solution.