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A mixture pf `H_(2) , N_(2)` and `O_(2)` occupying 100 ml underwent reaction so as to form `H_(2)O_(2)(l)` and `N_(2)H_(2)(g)` as the only products , causing the volume to contract by 60 ml. The remaining mixture was passed through pyrogallol causing a contraction of 10 ml . to the remaining mixture excess `H_(2)` was added and the above reaction was repeaped , causing a reduction in volume of 10 ml .(No other products are formed) What is the volume of `N_(20H_(2)(g)` formed in this reaction after adding excess of `H_(2)(g)`?A. 20 mlB. 30 mlC. 10 mlD. 40 ml |
Answer» Correct Answer - C correct answer will be option B as answered in the following link https://www.sarthaks.com/1468419/mixture-and-occupying-100-underwent-reaction-as-to-form-h-o-and-n-h-as-the-only-products |
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