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| 1. |
A MOD - 2 counter, the FF has a = 60 nsec. The NOR gate has a of 30 nsec. The clock frequency is |
| Answer» Clock period should be greater than or equal tpd MOD-12 → X FF = 4 x 60 = 240 n sec tpd of NOR gate = 30 n sec Total = 240 + 30 ⇒ 270 n sec . | |