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A molecule with molecular weight of 180.18g/mol is analyzed and found to contain 40.0% carbon, 6.72% hydrogen and 53.28% oxygen. What is the empirical and molecular formula of the molecules |
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Answer» Answer: The empirical formula is 2 O , and the molecular formula is some multiple of this. Explanation: In 100 g of the UNKNOWN, there are 40.0 ⋅ g 12.011 ⋅ g ⋅ m o l − 1
C ; 6.7 ⋅ g 1.00794 ⋅ g ⋅ m o l − 1
H ; and 53.5 ⋅ g 16.00 ⋅ g ⋅ m o l − 1
O . We divide thru to get, C : H : O
=
3.33 : 6.65 : 3.34 . When we divide each elemental ratio by the LOWEST number, we get an empirical formula of C H 2 O , i.e. NEAR enough to WHOLE numbers. Now the molecular formula is always a multiple of the empirical formula; i.e. ( EF ) n = MF . So 60.0 ⋅ g ⋅ m o l − 1 = n × ( 12.011 + 2 × 1.00794 + 16.00 ) g ⋅ m o l − 1 . Clearly n = 2 , and the molecular formula is 2 × ( C H 2 O )
=
C x H y O z
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