A monkey of mass m moves up on a massless string so as to just lift a block of mass M. After some time the monkey stops moving w.r.t the string. Find the magnitude of the change in the monkey's acceleration.

A monkey of mass m moves up on a massless string so as to just lift a

1.	A monkey of mass m moves up on a massless string so as to just lift a block of mass M. After some time the monkey stops moving w.r.t the string. Find the magnitude of the change in the monkey's acceleration.
Answer» Solution :When the MONKEY moves up with ACCELERATION .a. to lift the BLOCK `m(g+a)=Mg` `a=((M-m)g)/(m)` when monkey stops `a^(1)=((M-m)g)/(M+m)THEREFORE Delta a = a-a^(1)=(Mg(M-m))/(m(M+m))`