Saved Bookmarks
| 1. |
A monochromatic light is travelling in a medium of refractive index n = 1.6. It enters a stack of glass layers from the bottom side at an angle θ = 30°. The interfaces of the glass layers are parallel to each other. The refractive indices of different glass layers are monotonically decreasing as nm = n - mΔn, where nm is the refractive index of the mth slab and Δn = 0.1 (see the figure). The ray is refracted out parallel to the interface between the (m -1)th and mth slabs from the right side of the stack. What is the value of m? |
|
Answer» n sin θ = (n - mΔn) x sin 90° ⇒ m = n/2Δn ⇒ m = 8 |
|