A mother devides Rs. 207 into three parts such that the amount are in

1.	A mother devides Rs. 207 into three parts such that the amount are in A.P. and gives it to her three children. The product of the two least amounts that the children had Rs. 4623. Find the amount received by each child.
Answer» LET THREE PARTS ARE a-d,a,a+d NOW ,a-d+a+a+d=207 3a=207 a=69 AND ALSO,PRODUCT OF ANY TWO LEAST NUMBER IS 4623 SO, a(a-d)=4623 69(69-d)=4623 d=2 SO THREE PARTS ARE 67,69,71 a, a + d, a + 2d a + a + d + a + 2d = 207 3a + 3d = 207 3(a + d) = 207 a + d = 207/3 = 69 a x (a + d) = 4623 a x 69 = 4623 a = 4623/69 = 67 a = 67 67 + d = 69 ⇒ d = 69 - 67 = 2 a = Rs. 67 a + d = Rs. 69 a + 2d = Rs. 67 + (2 x 2) = Rs. 71

A mother devides Rs. 207 into three parts such that the amount are in A.P. and gives it to her three children. The product of the two least amounts that the children had Rs. 4623. Find the amount received by each child.

Answer» LET THREE PARTS ARE a-d,a,a+d
                              NOW ,a-d+a+a+d=207
                                                3a=207
                                                  a=69
AND ALSO,PRODUCT OF ANY TWO LEAST NUMBER IS 4623
              SO,         a(a-d)=4623
                             69(69-d)=4623
                                    d=2
         SO THREE PARTS ARE 67,69,71

a, a + d, a + 2d

a + a + d + a + 2d = 207

3a + 3d = 207

3(a + d) = 207

a + d = 207/3 = 69

a x (a + d) = 4623

a x 69 = 4623

a = 4623/69 = 67

a = 67

67 + d = 69

⇒ d = 69 - 67 = 2

a = Rs. 67

a + d = Rs. 69

a + 2d = Rs. 67 + (2 x 2) = Rs. 71

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