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| 1. |
A motor car running at the rate of 7m//s can be stopped by brakes in 10m. Prove that the total resistance to the motion when the brakes are on is one-fourth of the weight of the car. |
| Answer» Solution :`a=v^(2)-U^(2)//2s=-7^(2)//2xx10m//s^(2)`. `MU=ma//MG=-49/20xx9.8=-1//4`. Resistance = `mu mg =mg//4` | |