InterviewSolution
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InterviewSolution
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A motor cycle moving with a speed of `5 m//s` is subjected to an acceleration of `0.2 m//s^(2)`. Calculate the speed of the motor cycle after 10 second, and the distance travelled in this time. |
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Answer» Correct Answer - `7m//s` ; `60m` Here , `u = 5 m//s , a = 0.2 m//s^(2) , v = ? , t = 10 s , s = ?` ` v = u + at , v = 5 + 0.2 xx 10 = 7 m//s` From ` v^(2) - u^(2) = 2 as , s = ( v^(2) - u^(2))/( 2a) = ( 7^(2) - 5^(2))/( 2 xx 0.2 ) = 60 m` |
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