A motorcycle moving with a velocity of 72 km h^(-1) on a flat road takes a turn on the road at a point where the radius of curvature of the road is 20 m. The acceleration due to gravity is 10 ms^(-2). In order to avoid skidding, he must not bent with respect to the vertical plane by an angle greater than

A motorcycle moving with a velocity of 72 km h^(-1) on a flat road tak

1.	A motorcycle moving with a velocity of 72 km h^(-1) on a flat road takes a turn on the road at a point where the radius of curvature of the road is 20 m. The acceleration due to gravity is 10 ms^(-2). In order to avoid skidding, he must not bent with respect to the vertical plane by an angle greater than
Answer» `theta = tan^(-1) (2) ` `theta = tan ^(-1) (6) ` ` theta tan^(-1)(4)` ` theta = tan^(-1) ( 25.92)` Solution :Using the formula, for motorcycle not to SKID ` theta= tan^(-1) ""( v^2)/(RG)` here` r= 20m , v = 72kmh^(-1)= 72 XX (5)/(18) = 20ms^(-1)` `thereforetheta = tan^(-1)(( 20 xx 20)/( 20 xx 10)) or theta= tan^(-1)(2)`