A motorist drives north for 35.0minutes at 85km//h and then stops for 15 minutes. He next continues north , travelling 130km in 2.00hours.What is his total displacement? what is his average velocity?

A motorist drives north for 35.0minutes at 85km//h and then stops for

1.	A motorist drives north for 35.0minutes at 85km//h and then stops for 15 minutes. He next continues north , travelling 130km in 2.00hours.What is his total displacement? what is his average velocity?
Answer» Solution :`V_(1)=85kmph,t=35.0min,S_(2)=130km`. `S_(1)="DISPLACEMENT"=(85)/(60)xx35=43.58km` `S_(2) =130km` `s=s_(1)+s_(2)=49.58+130=179.58km` avetage velocity `V_(ave)=(s_(1)+s_(2)+s_(3))/(t_(1)+t_(2)+t_(3)` `=(49.58+0+130)/((35)/(60)+(15)/(60)+2)` `=(179.58xx60)/(170)=(10774.8)/(170)` `=63.38=63.4 km//hour`