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A moving coil galvanometer has 150 equal divisions. Its current sensitivity is 10-divisions per milliampere and voltage sensitivity is 2 divisions per millivolt. In order that each division reads 1 volt, the resistance in ohms needed to be connected in series with the coil will be -A. 99995B. 9995C. `10^(3)`D. `10^(3)` |
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Answer» Correct Answer - B (b) Voltage sensitivity `= ("Current sensitivity")/("Resistance of galvaonometer G")` `G = (10)/(2) Omega` Here `i_(g) =` Full scale deflection current `= (150)/(10) = 15 mA`. `V =` Voltage to be measued `= 150 xx 1 = 150 V`. Hence `R = (V)/(i_(g)) - G = (150)/(15 xx 10^(-3)) 5 = 99995 Omega` |
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