1.

A mussless right angled triangle is spended with its right angle comer. A mass of 100kg is suspended from another comer ll which subtiends an angle 53^(@). Find the mass that should be suspended from other comer so that (hypolemic) remains horizontal.

Answer»

SOLUTION :From the principle of woments, `10xxgxx x_(1)-mxxg xx x_(2)`
`100 cos53^(@)-mxxcos 37^(@)`
Where, `x_(1) and x_(2)` are the ARM lengths. The right angle triangle with angles `37^(@).53^(@)` 53 and is a special triangle which has the respective SIDES in the ratio, 3:45 us SHOWN in the diagram. Substituting the values in equation (1)

`100xx cos53^(@)= m xx cos 37^(@)`
`100xx(3)/(5)=mxx(4)/(5)`
`m=100xx(3)/(4)`
`m=75 g`


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