1.

A nail is located below the point of suspension of a simple pendulum of length l. The bob is released from horizontal position. If the bob loops a verticle circle with nail as centre, find the distance of nail from point of suspension.

Answer»

Solution :Form the principle of conservation of mechanical energy
PE at the horizontal position = KE at the LOWEST position.
`mgl = (1)/(2) mv^(2)`
To loop the vertical circle ,
`V^(2)=5g(1-X)` where .x. is the distance of nail from point of SUSPENSION, and .v. is the velocity at lowest point of path.
`(mgl=(1)/(2)m.5g (l-x)), l=(5)/(2)(l-x), "" x = 3l//5`


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