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A negligibly small current is passed through a wire of length 15 m and uniform cross-section `6.0 xx 10^(-7) m^(2)`, and its resistance is measured to be `5.0 Omega`. What is the resistivity of the material at the temperature of the experiment ? |
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Answer» Length of the wire, `l = 15` m Area of the cross-section of the wire, `a = 6.0 xx 10^(-7) m^(2)` Resistance of the material of the wire, `R = 5.0 Omega` Resistivity of the material of the wire `= rho` Resistance is related with the resistivity as `R = rho (l)/(A)` `rho = (RA)/(l)` `= (5 xx 6 xx 10^(-7))/(15) = 2 xx 10^(-7) Omega` m Therefore, the resistivity of the material is `2 xx 10^(-7) Omega` m. |
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