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A negligibly small current is passed through a wire of length 15 m and uniform cross-section 6 × 10-7 m2, and its resistance is measured to be 5 Ω. What is the resistivity of the material at the temperature of the experiment? |
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Answer» Given: l = 15 m, A = 6.0 × 10-7 m2, R = 5 Ω To find: Resistivity (ρ) Formula: ρ = \(\frac{RA}{l}\) Calculation: From formula, ρ = \(\frac{5\times6\times10^{-7}}{15}\) ∴ ρ = 2 × 10-7 Ω m |
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