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A network of four each of `12 mu F` capacitance is connected to a `500 V` apply as shown in Fig. (a) Equivalent capacitance of the network. (b) Charge on each capacitor. |
Answer» Correct Answer - (a) `16 muF` (b) `q_(1) = q_(2) = q_(3) = 2000 muC, q_(4) = 6000 muC` Here, `C_(1), C_(2), C_(3)` are in series. `C_(123) = (12 muF)/(3) = 4 muF` As `C_(4)` is in parallel with this combination, `:. C_(eq) = 4+12 = 16 muF` `q_(1) = q_(2) = q_(3) = C_(123) V = 4 muF xx 500 = 2000 muC` `q_(4) = C_(4) V = 12 muF xx 500 V = 6000 muC` |
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