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A network of resistors is connected to a 16 V battery with internal resistance of 1Ω., as shown in the following figure. Compute the equivalent resistance of the network. |
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Answer» Equivalent Resistance = R1.R2/ (R1+R2) +R3+ R4.R5/(R4+R5) = [(4 × 4)/(4 + 4)] + 1 + [(12 × 6)/(12 + 6)] Ω = 7 Ω |
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