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A neutral atom of an element has 2 K, 8L and 5M electrons. Find out the following. (ii) Total number of s-eelctrons. |
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Answer» Solution :The ELECTRONIC CONFIGURATION of the ELEMENT with 2K, 8L and 5M ELECTRONS will be `1s^2 2s^2 2p_x^2 2p_y^2 2p_z^2 3s^2 3p_x^1 3p_x^1 p_y^1 3p_z^1` Total number of s-electrons = 2 + 2 + 2 = 6. |
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