A neutral point is found on the axis of a bar magnet at a distance of `10cm` from one end. If the length of the magnet is `10cm` and `H=0*3gauss`, find the magnetic moment of the magnet.

A neutral point is found on the axis of a bar magnet at a distance of

1.	A neutral point is found on the axis of a bar magnet at a distance of `10cm` from one end. If the length of the magnet is `10cm` and `H=0*3gauss`, find the magnetic moment of the magnet.
Answer» Correct Answer - `0506Am^2` Here, `2l=10cm`, `H=03G`, `M=?` `r=10+l=10+5=15cm=15xx10^-2m` As neutral point is on the axis of bar magnet, therefore, `H=(mu_0)/(4pi)(2M)/(r^3)=10^-7(2xxM)/((15xx10^-2)^3)` `M=((15xx10^-2)^3H)/(2xx10^-7)=(3375xx10^-6xx03xx10^-4)/(2xx10^-7)` `M=50625xx10^-3=0*506Am^2`

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A neutral point is found on the axis of a bar magnet at a distance of `10cm` from one end. If the length of the magnet is `10cm` and `H=0*3gauss`, find the magnetic moment of the magnet.

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