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A non conducting ring of radius `R_(1)` is charged such that the linear charge density is `lambda_(1)cos^(2)theta` where `theta` is the polar angle. If the radius is increased to `R_(2)` keeping the charge constant, the linear charge density is changed to `lambda_(2)cos^(2)theta`. The relation connecting `R_(1)`, `R_(2)lambda_(1)` and `lambda_(2)` will beA. `lambda_(1)//R_(1)=lambda_(2)//R_(2)`B. `lambda_(1)//R_(2)=lambda_(2)//R_(1)`C. `lambda_(1)lambda_(2)=R_(1)R_(2)`D. `lambda_(1)^(2)R_(1)=lambda_(2)^(2)R_(2)` |
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Answer» Total charge `Q-int_(0)^(2x)lambdacos^(2)thetaRd theta=pilambdaR` Hence `pi lambda_(1)R_(1)=pilambda_(2)R_(2)` `rArr (lambda_(1))/(R_(2))=(lambda_(2))/(R_(1))` |
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