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A noraml to the parabola at a point A on the parabola whose equation is y^(2)=2013x cuts the axis of x at N. AN is produced to the point B such that NB=1/2AN. If the normals through any point of the parabola y^(2)=2013x, cut the line 2x - 2013 = 0, in points whose ordinates are in AP, then the slopes of these normals are in |
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Answer» AP |
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