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A normal to x2a2+y2b2=1 meets the axes in L and M. The perpendiculars to the axes through L and M intersect at P. Then the equation to the locus of P is |
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Answer» A normal to x2a2+y2b2=1 meets the axes in L and M. The perpendiculars to the axes through L and M intersect at P. Then the equation to the locus of P is |
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