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A nuclear reaction along with the masses of the particle taking part in it is as follows `underset("1.002 amu")(A)+underset("1.004 amu")(B) to underset("1.001 amu")(C)+underset("1.003 amu")(D)+QMeV` the energy Q is liberated in the reaction isA. 1.234 MeVB. 0.931 MeVC. 0.465 MeVD. 1.862 MeV |
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Answer» Correct Answer - D `Q=(1.002+1.004-1.001-1.003)(931.5)MeV` `=1.863MeV` |
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