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A nucleus with Z = 92 emits the following in a sequence: α, β−, β−, α, α, α, α, α, β−, β−, α, β+, β+, α . Then, the Z of the resultant nucleus is |
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Answer» A nucleus with Z = 92 emits the following in a sequence: α, β−, β−, α, α, α, α, α, β−, β−, α, β+, β+, α . Then, the Z of the resultant nucleus is |
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