A number 34A is exactly divisible by 2 and leaves a remainder 1, when

1.	A number 34A is exactly divisible by 2 and leaves a remainder 1, when divided by 5, find A.
Answer» If 34A Is divisible by 2 then the remainder should be equal to 0. ∴ A should be equal to 0, 2, 4, 6, 8. ∴ 340, 342, 344, 346, 348 are divisible by 2 and gives the remainder ‘0’. Among these 346 is divisible by 5 and gives the remainder 1. ∴ 346 → 6/5(R = 1) ∴ The value of A = 6.

A number 34A is exactly divisible by 2 and leaves a remainder 1, when divided by 5, find A.

Answer»

If 34A Is divisible by 2 then the remainder should be equal to 0.

∴ A should be equal to 0, 2, 4, 6, 8.

∴ 340, 342, 344, 346, 348 are divisible by 2 and gives the remainder ‘0’.

Among these 346 is divisible by 5 and gives the remainder 1.

∴ 346 → 6/5(R = 1)

∴ The value of A = 6.