A number consists of two digits whose sum is 8. If 18 is subtracted fr

1.	A number consists of two digits whose sum is 8. If 18 is subtracted from the number, the digits are reversed. The number is:1. 322. 713. 534. 80
Answer» Correct Answer - Option 3 : 53 Given: The sum of digits of the number = 8. Calculation: Let the two-digit number be 10x + y Where the unit digit and the tenth place digit of the number is y and x respectively. After reversing the digits the number becomes 10y + x. According to the 1^st condition, x + y = 8 ----(1) According to the 2^nd condition, 10x + y - 18 = 10y + x ⇒ 9x - 9y = 18 ⇒ 9(x - y) = 18 ⇒ x - y = 2 ----(2) by adding equation (1) and equation (2), we get 2x = 10 ⇒ x = 5 On putting the value of x in equation (1), we get 5 + y = 8 ⇒ y = 8 - 5 ⇒ y = 3 So, the two-digit number is 10 × 5 + 3 ∴ The two-digut number is 53.

A number consists of two digits whose sum is 8. If 18 is subtracted from the number, the digits are reversed. The number is:1. 322. 713. 534. 80

Answer» Correct Answer - Option 3 : 53

Given:

The sum of digits of the number = 8.

Calculation:

Let the two-digit number be 10x + y

Where the unit digit and the tenth place digit of the number is y and x respectively.

After reversing the digits the number becomes 10y + x.

According to the 1^st condition,

x + y = 8 ----(1)

According to the 2^nd condition,

10x + y - 18 = 10y + x

⇒ 9x - 9y = 18

⇒ 9(x - y) = 18

⇒ x - y = 2 ----(2)

by adding equation (1) and equation (2), we get

2x = 10

⇒ x = 5

On putting the value of x in equation (1), we get

5 + y = 8

⇒ y = 8 - 5

⇒ y = 3

So, the two-digit number is 10 × 5 + 3

∴ The two-digut number is 53.

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